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Assoli18 [71]
3 years ago
12

If a two story home has a ground floor of 25*30 feet and second floor of 20*30 feet, what is the total square footage of the hom

e?
Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer: 1350 ft^2

Step-by-step explanation:

The total square footage of the home will be equal to the sum of the areas of each floor.

We know that the ground floor is 25 ft by 30ft,  which can be thought of as a rectangle with a length of 25ft and a width of 30 ft.

We know that te area of a rectangle of width W and length L is:

A = L*W

then the area of the ground floor is:

A = 25ft*30ft = 750 ft^2

And the second floor is 20ft by 30ft, then using the same approach as above, the area of the second floor will be:

A = 20ft*30ft = 600ft^2

Then the total square footage of the home is:

SF = 750ft^2 + 600ft^2 = 1350 ft^2

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Add and simplify the result, if possible. x/18 + 3/18
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\frac{x}{18}  and  \frac{3}{18} both have a common denominator, so you can combine them into a single fraction:

\frac{x}{18}+\frac{3}{18}=\frac{x+3}{18}

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8 0
3 years ago
In the textile industry, a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material.
Naily [24]

Answer:

b. Binomial distribution.

Step-by-step explanation:

As a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material which shows that only two possible outcomes with fixed number of trials are present here, so the probability distribution that has the greatest chance of applying to this situation is a binomial distribution that summarizes the possibility that a value will take one of two independent values under a provided set of parameters.

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3 years ago
Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
Vlad1618 [11]

<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Find the perimeter of the field ?

<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

6 0
3 years ago
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Olenka [21]

Answer:

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Step-by-step explanation:

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Write the following number by entering one digit in each box of the place value chart.​
ratelena [41]

Answer:

  see the attached

Step-by-step explanation:

Each digit goes in the place corresponding to its place value.

When no digit has a given place value, a placeholder is used. That is the purpose of zero, a great invention in the history of mathematics. It makes place-value number systems possible.

8 0
3 years ago
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