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3 years ago

DONT IGNORE!!! I NEED HELP: NO LINKSS

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

39 ft²

Step-by-step explanation:

11 ft × 3 ft = 33 ft²

2 ft × 3 ft = 6 ft²

33 ft² + 6 ft² = 39 ft²

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One number is 3 times more than another number. Their sum is 20. What are the two numbers?

Georgia [21]

3x=y
X+Y=20
5=x and 15=y are the answer. You can use elimination or substitution or guess and check!

6 0

3 years ago

Read 2 more answers

Nancy’s morning routine involves getting dressed , eating breakfast, making her bed , and driving to work . Nancy spends 1/3 of

grin007 [14]

Answer: Nancy needs 26 minutes to driving to work.

Explanation:

Since we have given that

Time taken in eating breakfast = 10 minutes

Time taken in making her bed = 5 minutes

Let the total time taken by her in doing routine activities be x

Time taken in getting dressed is given by

$\frac{1}{3}x$

So, According to question,

$\frac{x}{3}+10+5=35\frac{1}{2}\\\\\frac{x}{3}+15=\frac{71}{2}\\\\\frac{x}{3}=\frac{71}{2}-15\\\\\frac{x}{3}=\frac{71-30}{2}=\frac{41}{2}\\\\x=\frac{123}{2}$

Now, we need to find the time taken in driving to work which is given by

$\frac{123}{{2}-\frac{71}{2}=\frac{52}{2}=26\ minutes$

Hence, Nancy needs 26 minutes to driving to work.

6 0

3 years ago

Josie is training for a race. The ratio of

anzhelika [568]

The number of minutes that Josie will take is 80 minutes.

Explanation:

Explanation:

Ratio of the number of minutes to the number of miles = $\frac{24}{3}$

Number of miles = 10

Number of minutes = ?

Let x be the number of minutes

According to the question,

$\frac{24}{3} = \frac{x}{10} \\\\x = \frac{240}{3} \\\\x = 80$

Therefore, the number of minutes that Josie will take is 80 minutes.

6 0

3 years ago

A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi

lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

20 tosses, hence $n = 20$ .
Fair coin, hence $p = 0.5$ .

The probability is P(X = 10), thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762$

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

$\mu = np = 20(0.5) = 10$

$\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}$

Using continuity correction, this probability is $P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5)$ , which is the p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.