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Over [174]
3 years ago
6

2

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

5) option c

6) option d

7) option d

8) option b

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What is the equation of the line that contains the
slavikrds [6]

Answer:

B

Step-by-step explanation:

<em>y</em><em>=</em><em>kx</em><em>+</em><em>m</em>

<em>k</em><em>=</em><em>y2</em><em>+</em><em>y1</em><em> </em><em>/</em><em> </em><em>x2</em><em>+</em><em>x1</em><em> </em>

(3,5) and (7,9)

k=(9-5)/(7-3)=4/4=1

Now we want to find out what <em>m</em><em> </em>is. This is by inserting a point in the equation of the line y=kx+m.

so I'll pick (3,5)

5=1×3+m

m= 2

To check if it's correct we could try it with the other point, (7,9).

9=1×7+m

m=2

Therefor the equation would be. y=1x+2

5 0
4 years ago
Suppose the weights of tight ends in a football league are normally distributed such that σ2=400. A sample of 11 tight ends was
AlladinOne [14]

Answer:

217.636-1.96\frac{20}{\sqrt{11}}=205.817    

217.636+1.96\frac{20}{\sqrt{11}}=229.455    

So on this case the 95% confidence interval would be given by (205.82;229.46)    

Step-by-step explanation:

Assuming the following data: Weight 150 169 170 196 200 218 219 262 269 270 271

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma= \sqrt{400}= 20 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean we can use the following formula:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

The mean calculated for this case is \bar X=217.636

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

217.636-1.96\frac{20}{\sqrt{11}}=205.817    

217.636+1.96\frac{20}{\sqrt{11}}=229.455    

So on this case the 95% confidence interval would be given by (205.82;229.46)    

8 0
4 years ago
Is this relationship a function? (1,2) (2,9) (3,-2) (4,8)?
olganol [36]

Answer:

yes, it's a function

Step-by-step explanation:

A function relates one input to one output, and it's "only" one output.

6 0
4 years ago
Find AC please, help is very much appreciated.
fenix001 [56]

Answer:

AC ≈ 67.9

Step-by-step explanation:

15² = 9 (3x + 1 + 9)

225 = 9 (3x + 10)

225 = 27x + 90

135 = 27x

x ≈ 19.29

AC = (3x + 1 + 9)

AC = 3 (19.2857...) + 1 + 9

AC = 57.857... + 1 + 9

AC =  57.857... + 10

AC ≈ 67.9

4 0
3 years ago
A pitcher of lemonade in Manny's refrigerator was full in the morning. In the afternoon, he drank two glasses of lemonade. Each
Snezhnost [94]
To find how much lemonade the pitcher can hold, you will add the amounts that he drank and remained to get a total.  This total would be the starting amount.

8 oz + 8 oz + 24 oz = 40 ounces

The pitcher originally held 40 ounces of lemonade.
5 0
3 years ago
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