All categories

2 years ago

2

Mathematics

1 answer:

FrozenT [24]2 years ago

7 0

Answer:

5) option c

6) option d

7) option d

8) option b

You might be interested in

Find the area of the shaded region, round answer to nearest tenth

den301095 [7]

Answer:

vhebvsbvvebn

Step-by-step explanation:

3 0

2 years ago

the cost of the cab was $3 for each mile plus $20. Write the equation for the situation and complete the table to find the total

jok3333 [9.3K]

3+20=23 is the answer

5 0

2 years ago

Find the distance between (-8, 4) and (-8, -2). 10 units 2 units 6 units 8 units

svp [43]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please help with #s 8, 9, 10

densk [106]

Answer:

8. y=-1/2-7

9. Parallel

10. Neither

Hope this helps!

6 0

2 years ago

Read 2 more answers

Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

a. The system of equations that models the situation is....

$0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40$

b. The solution to the system: x = 2 and y = 4

The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

7 0

3 years ago