(93+67+78+44+123)/5=405/5=81 pizzas per day on average
C is your answer.
Given:
To verify:
for the given values.
Solution:
We have,
We need to verify .
Taking left hand side, we get
Taking LCM, we get
Taking right hand side, we get
Taking LCM, we get
Now,
Hence proved.
Plug in the values of the ordered pairs into the equations.
41 = 5(8) + 1
41 = 40 + 1
41 = 41
So, A y = 5x + 1 is the answer.
Answer:
a: 0.08, or 8% chance he wins all 3
b: 0.42, or 42% chance he wins 2
Step-by-step explanation:
P(win A) = 0.8
P(lose A) = 0.2
P(win B) = 0.5
P(lose B) = 0.5
P(win C) = 0.2
P(lose C) = 0.8
The situations are independent, so we multiply probabilities together.
To win all 3: P(win A)*P(win B)*P(win C) = 0.8*0.5*.02 = 0.08
To win 2 of the 3 there are 3 ways to do this. We add up the probabilities of the 3 situations...
P(win A)*P(win B)*(lose C) = 0.8*0.5*0.8 = 0.32
P(win A)*P(lose B)*P(win C) = 0.8*0.5*0.2 = 0.08
P(lose A)*P(win B)*P(win C) = 0.2*0.5*.02 = 0.02
0.32 + 0.08 + 0.02 = 0.42
I know how you feel. Can I get a better picture