No, Vijay cannot fit all cubes into the box.
Solution:
Total number of cubes = 50
Volume of each cube = 1 cubic inch
Number of cubes fit in the bottom of the box = 12
Area of the box<em> = l</em> × <em>b</em> = 12 square inch
Height of the box = 4 inch
Volume of the box = <em> l</em> × <em>b </em>× h
= 12 × 4
Volume of the box = 48 cubic inch
So, 48 cubes can only fit in the box.
Hence, Vijay cannot fit 50 cubes into the box.
Standard deviation (s): 2.7386127875258
Answer: 0.3439
Step-by-step explanation:
Given :The last four digits for telephone numbers are randomly selected (with replacement).
Here , each position can be occupied with any of the digit independently .
Total digits = 10
Total digits other than 0 = 9
For each digits , the probability that it is not 0 = 
If we select 4 digits , The probability of getting no 0 =
(By multiplication rule of independent events)
Now , the probability that for one such phone number, the last four digits include at least one 0. = 1- P(none of them is 0)
=1- 0.6561=0.3439
Hence, the probability that for one such phone number, the last four digits include at least one 0. is 0.3439 .