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natulia [17]
3 years ago
13

Can someone please help me? thank you

Mathematics
1 answer:
balandron [24]3 years ago
8 0

Answer:

c = (ef-ab)/d

Step-by-step explanation:

ab+cd = ef

Subtract ab from each side

ab+cd -ab = ef-ab

cd = ef-ab

Divide by d

cd /d =(ef-ab)/d

c = (ef-ab)/d

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2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
15 points! Thanks so much!!
Georgia [21]
For this question it is the difference of two perfect squares. This means your final answer will be (2x - 5)(2x + 5). This answer is not listed so it would be none of the above.

After review, B technically works because it is the difference of two perfect squares. This allows you to take the square root of each term while ignoring the sign and then place that back in with the original sign.
5 0
3 years ago
Read 2 more answers
Angle a and angle b are verticle angles if m <br> PLEASE HELPLO
klemol [59]
Can we get a picture please
3 0
3 years ago
A farmer has 96 apples to sell at the farmers market. She wants to bag the apples before going. How many ways can the farmer bag
Tcecarenko [31]

Answer and explanation:

Farmer's number of apples = 96 apples

Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag

And also all apples in each bag are equal

We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder

4 can divide 96= 24

5 cannot divide 96 without remainder

6 can divide 96 =16

7 cannot divide 96 without remainder

8 can divide 96=12

9 cannot divide 96 without remainder

10 cannot divide 96 without remainder

From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10

4 apples = 24 bags

6 apples = 16 bags

8 apples = 12 bags

Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples

8 0
3 years ago
Simplify -4.5 + (-1.5)
mojhsa [17]

-4.5 + (-1.5)

-4.5 + 1.5

-6

5 0
3 years ago
Read 2 more answers
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