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Margarita [4]
3 years ago
6

I need help asap please! tia​

Mathematics
1 answer:
quester [9]3 years ago
7 0

Answer:

Answer is b. The distance between -5 and 0.

Step-by-step explanation:

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Which unit rate is the lowest price per ounce?
marin [14]

Answer:

Choice B

Step-by-step explanation:

Divide both of the choices by the price and ounces. You will find that the unit rate of choice B is lower.

Work

3.49/25=0.14

4.79/45=0.106

Therefore choice B has the lowest unit rate and that is the answer!

8 0
3 years ago
Every year, Calaveras County holds a frog jumping contest. Mia entered her frog into the 100-yard contest and it completed the r
worty [1.4K]

Answer:

Step-by-step explanation:

For Mia:

distance,d = 100 yard

time, t = 2 min 33 sec = 153 s

Speed = distance / time

speed = 100 / 153 = 0.65 yard/s

For Larisa:

distance, d = 350 yard

time, t = 5 min 18 sec = 318 s

speed = 350 / 318 = 1.1 yard/s

So, the speed of Larisa is more than the speed of Mia.

7 0
3 years ago
I think it’s the third one
Zigmanuir [339]
It’s third to the one
7 0
3 years ago
Read 2 more answers
which pair of numbers is relatively prime A.)30 and 138 B.)34 and 137 C.)318 and 1443 D.)3000 and 30,616
Dahasolnce [82]
I think it is the letter B
5 0
3 years ago
Read 2 more answers
Basic Computation: Testing M1 2 M2 A random sample of 49 measurements from a population with population standard deviation 3 had
Elenna [48]

Answer:

The sample statistics follows a standard normal distribution since the sample size are large enough.

Step-by-step explanation:

Given that:

<u>First population:</u>

Sample size n_1 = 49

Population standard deviation \sigma_1  = 3

Sample mean \overline x _1= 10

<u>Second population:</u>

Sample size n_2 = 64

Population standard deviation \sigma_2= 4

Sample mean \overline x_2= 12

The sample statistics follows a standard normal distribution since the sample size are large enough.

The null and alternative hypotheses can be computed as:

\mathbf{H_o:\mu_1=\mu_2}

\mathbf{H_1:\mu_1\ne\mu_2}

Level of significance  = 0.01

Using the  Z-test statistics;

Z = \dfrac{\overline x_1 - \overline x_2}{\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}}

Z = \dfrac{10- 12}{\sqrt{\dfrac{3^2}{49} + \dfrac{4^2}{64}}}

Z = \dfrac{-2}{\sqrt{\dfrac{9}{49} + \dfrac{16}{64}}}

Z = \dfrac{-2}{\sqrt{0.18367 +0.25}}

Z = \dfrac{-2}{\sqrt{0.43367}}

Z = \dfrac{-2}{0.658536}

Z = - 3.037

Z \simeq - 3.04

The P-value = 2P (z < -3.04)

From the z tables

= 2 × (0.00118)

= 0.00236

Thus, since P-value is less than the level of significance, we fail to reject the null hypotheses H_o

5 0
3 years ago
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