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3 years ago

Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70

Mathematics

1 answer:

Volgvan3 years ago

5 0

Answer:

9, 11 and 13

Step-by-step explanation:

Let the integers be x, x + 2, x + 4.

x + 2(x + 2) + 3(x + 4) = 70

x + 2x + 4 + 3x + 12 = 70

6x = 54

x = 9

therefore the three integers are 9, 11 and 13

This is a question on forming and solving algebraic equations. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

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0.04 = 1/10 of x

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Divide both sides by x.

x = 0.04/0.10

x = 0.4

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bazaltina [42]

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y2-y1/x2-x1

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-4x + 7y = 56 Find x & y intercepts of equation

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Terry is skiing down a steep hill. Terry's elevation E(t)

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Step-by-step explanation:

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3 years ago

Sophie, Jonah, and Chase have a total of $89 in their wallets. Sophie has $6 less than Chase and Jonah has 3 times what Chase ha

Marrrta [24]

So first you need to find a formula for who has what!

Because nobody said what chase had, chase is our variable!

Chase = x
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Now you will put all of this in an equation- adding everybody together! The total is 89 so that will be what’s after the equal sign!

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Now you will solve this like a regular equation! First, you have to move the -6 to the right so you will do the inverse operation (the opposite sign) and add 6 to both sides! 89+6 is 95 and -6+6 is 0, so the 6 on the left cancels out and isn’t there anymore!

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Marat540 [252]

Answer:

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Step-by-step explanation:

in order for me to answer you need to pit the problem

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