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Sloan [31]
3 years ago
13

1. (k+7)² =2892. (2s-1)² =2253. (x-4)² =169please help me answer these :)

Mathematics
2 answers:
Paul [167]3 years ago
8 0
1. \ \ \ (k+7)^2 =289\\\\\Leftrightarrow\ \ \ k+7= \sqrt{289} \ \ \ or\ \ \ \ k+7=- \sqrt{289}\\\\k=17-7=10\ \ \ \ \ \ \ or\ \ \  \ k=-17-7=-24 \\\\2.\ \ \  (2s-1)^2 =225\\\\\Leftrightarrow\ \ \ 2s-1= \sqrt{225} \ \ \ or\ \ \ \ 2s-1=- \sqrt{225}\\\\2s=15+1\ \ \ \ \ \ \ or\ \ \  \ 2s=-15+1\\2s=16\ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ 2s=-14\\s=8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ s=-7 \\\\

3.\ \ \  (x-4)^2 =169\\\\\Leftrightarrow\ \ \ x-4= \sqrt{169} \ \ \ or\ \ \ \ x-4=- \sqrt{169}\\\\x=13+4=17\ \ \ \ \ \ \ or\ \ \ \ x=-13+4=-9
professor190 [17]3 years ago
6 0
(k+7)^2 =289\\
|k+7|=17\\
k+7=17\vee k+7=-17\\
k=10 \vee k=-24

(2s-1)^2 =225\\
|2s-1|=15\\
2s-1=15\vee 2s-1=-15\\
2s=16 \vee 2s=-14\\
s=8 \vee s=-7

(x-4)^2 =169\\
|x-4|=13\\
x-4=13 \vee x-4=-13\\
x=17 \vee x=-9
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-4 (2x + 13) + 3x = 80<br> How do you solve this out and get the answer
shusha [124]
Hey :)

x= -12

Use the distributive property to multiply −4 by 2x+13


−8x−52=3x+80
Subtract 3x from both sides
−8x−52−3x=80


Combine −8x and −3x to get −11x
−11x−52=80

Add 52 to both sides
−11x=80+52


Add 80 and 52 to get 132
−11x=132


Divide both sides by −11
x= 132/-11
​

Divide 132 by −11 to get −12
x=−12


Hope this helps :)
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Step-by-step explanation:

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Step-by-step explanation:

Answer 1...

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