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3 years ago

What is the missing side length?

Mathematics

1 answer:

Yanka [14]3 years ago

4 0

Answer:

Step-by-step explanation:

5^2+12^2=13^2. It is a right triangle

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Add an equation and answer

trapecia [35]

Answer:

Currently temperature = 35°F

Rate of descend = 4°F

We have to reach = -1°F

Temperature to get cooled down = |-1 + 35| (The two lines mean absolute value)

=> 36°F

Hours = Total temperature to get cooled / Rate

=> 36 / 4

=> 9 hours

Equation = 4x = |1 + 35|

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

3 0

3 years ago

Write 2.96 as a mixed number or fraction in simplest form show your work

Readme [11.4K]

<h3>Hey there </h3><h3>Improper Fraction: $\frac{74}{25 }$ </h3><h3>Mixed number/ Fraction : $2\frac{24}{25}$ </h3><h3>Check to see if it gives your decimal </h3><h3> $\frac{296/4}{100/4}$ </h3><h3> $\frac{296}{4}$ → $74$ </h3><h3> $\frac{100}{4}$ → $25$ </h3><h3>We now have: $\frac{74}{25}$ </h3><h3>Therefore, your result ( $answer$ ) is: $2\frac{24}{25}$ </h3><h3>Good luck on your assignment and enjoy your day!</h3><h3>~ $LoveYourselfFirst:)$ </h3>

3 0

3 years ago

AaBbCc x AaBbCc (use for all 3 questions) 1. What is the probability that this individual will: AABBcc 2. What is the probabilit

tankabanditka [31]

Answer: 1. P = 1/64

2. P = 1/32

3. P = 1/8

Step-by-step explanation:

In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:

For crossing Aa x Aa:

A a

A AA Aa

a Aa aa

For crossing Bb x Bb:

B b

B BB Bb

b Bb bb

For crossing Cc x Cc:

C c

C CC Cc

c Cc cc

We can separate them because they are assorted independently.

For offspring with <u>genotype</u> <u>AABBcc</u>, probability will be:

P(AA) = 1/4

P(BB) = 1/4

P(cc) = 1/4

As all three probabilities has to happen at the same time, it is a "E" rule:

P(AABBcc) = $(\frac{1}{4}) (\frac{1}{4}) (\frac{1}{4})$

P(AABBcc) = 1/64

Probability for the individual to be AABBcc is 1/64 or 1.56%.

<u>Genotype</u> <u>AaBBcc</u>:

P(Aa) = 2/4 = 1/2

P(BB) = 1/4

P(cc) = 1/4

P(AaBBcc) = $(\frac{1}{2}) (\frac{1}{4}) (\frac{1}{4})$

P(AaBBcc) = 1/32

Probability for the individual to be AaBBcc is 1/32 or 3.12%

<u>Genotype</u> <u>AaBbCc</u>:

P(Aa) = 1/2

P(Bb) = 1/2

P(Cc) = 1/2

P(AaBbCc) = $(\frac{1}{2}) (\frac{1}{2}) (\frac{1}{2})$

P(AaBbCc) = 1/8

Probability for the individual to be AaBbCc is 1/8 or 12.5%.

4 0

3 years ago

70% of 350 is what number?

Kruka [31]

245 would be your answer

3 0

3 years ago

Read 2 more answers

If m 2=27, what is the measure of the supplement of

Dmitry [639]

Supplementary angles sum to 180°

180-27=153°

4 0

4 years ago