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PtichkaEL [24]
2 years ago
10

I need help pls is only 1 question

Mathematics
1 answer:
Yanka [14]2 years ago
4 0

Answer:

T = 1300

Step-by-step explanation:

Given

Radius, r = 9\ in

Height, h = 14\ in

<em>See attachment</em>

<em></em>

Required

Determine the total surface area, T

T is calculated using:

T = 2\pi r(r + h)

Substitute values for r and h

T = 2\pi  * 9(9 + 14)

T = 2\pi  * 9(23)

Remove bracket

T = 2\pi  * 9*23

T = 2\pi  * 207

Take \pi = 3.14

So, we have:

T = 2 * 3.14 * 207

T = 1299.96

T = 1300 --- approximated.

<em>Hence, the surface area is 1300 square inch</em>

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Step-by-step explanation:

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The image of point (−3, 5) under translation T is (6, -8). What is the image of point (4, 7) under the same translation?
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Apply this translation T to (4,7) and you get (13,-6).

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Can you define f(0, 0) = c for some c that extends f(x, y) to be continuous at (0, 0)? If so, for what value of c? If not, expla
Ahat [919]

(i) Yes. Simplify f(x,y).

\displaystyle \frac{x^2 - x^2y^2 + y^2}{x^2 + y^2} = 1 - \frac{x^2y^2}{x^2 + y^2}

Now compute the limit by converting to polar coordinates.

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\displaystyle \lim_{(x,y)\to(0,0)} f(x,y) = 1

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and

\dfrac{x^2y^2}{x^2+y^2} \ge 0 \ge -x^2 - y^2

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\displaystyle \lim_{(x,y)\to(0,0)} -(x^2+y^2) = 0

\displaystyle \lim_{(x,y)\to(0,0)} (x^2+y^2) = 0

so by the squeeze theorem,

\displaystyle 0 \le \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} \le 0 \implies \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = 0

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Answer:

Step-by-step explanation:

x=-2, x=3

---------------

x^2+5x+6=(-2)^2+5(-2)+6=(-2)(-2)-10+6=4-10+6=-6+6=0

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---------------------------------------------------------------

x^2-x-6=(-2)^2-(-2)-6=4+2-6=6-6=0

x^2-x-6=3^2-3-6=9-3-6=6-6=0

-----------------------------------------------------

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