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Brums [2.3K]
3 years ago
14

It takes billy 6 minutes to walk 1.5 km. How long will it take billy to walk 9km?

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0

Answer:

\boxed{\tt 36 \ minutes}

Step-by-step explanation:

Let's make a proportion using the following setup:

\frac{minutes}{kilometers} =\frac{minutes}{kilometers} \\

We know it takes Billy 6 minutes to walk 1.5 kilometers.

\frac{6\ minutes}{1.5\ kilometers} =\frac{minutes}{kilometers}

We don't know how long it takes him to walk 9 kilometers, so we can say it takes him x minutes to walk 9 kilometers.

\frac{6\ minutes}{1.5\ kilometers} =\frac{x\ minutes}{9\ kilometers}

\frac{6}{1.5} =\frac{x}{9}

Now, solve for x. To do this, isolate x on one side of the proportion. x is being divided by 9. The inverse of division is multiplication. Multiply both sides of the proportion by 9.

9*\frac{6}{1.5} =\frac{x}{9}*9

9*\frac{6}{1.5} =x

9*4=x

36=x

x= 36 minutes

It will take Billy 36 minutes to walk 9 kilometers.

Pepsi [2]3 years ago
7 0

Answer:

It will take Billy 36 minutes to walk 9km.

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Explanation:

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A storage shed is to be built in the shape of a box with a square base. It is to have a volume of 686 cubic feet. The concrete f
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Answer:

Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

Step-by-step explanation:

Given that, a storage shade is be built in the shape of a box with a square base.

Let the height of the box be h and the length of one side of the square base be x.

The area of the square base is = side²

                                                    =x²

The volume of the box is = area of the base × height

                                          =x²h

According to the problem,

x²h=686

\Rightarrow h=\frac{686}{x^2} .......(1)

The concrete for the base costs $5 per square foot.

The material for the base costs =$ 5x²

The material for the roof costs $9 per square foot.

The material cost for roof is =$9x²

The material for the sides costs $3.50  per square foot.

The material cost for sides =$(3.50× 4xh )

                                             =$14xh

Total cost =$(5x²+9x²+14xh)

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Let

C = 14x²+14 xh

Putting h=\frac{686}{x^2}

C=14x^2+14 x.\frac{686}{x^2}

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Differentiating with respect to x

C'= 28x-\frac{9604}{x^2}

Again differentiating with respect to x

C''= 28+\frac{19208}{x^2}

To find the dimension set C'=0

28x-\frac{9604}{x^2}=0

\Rightarrow 28x=\frac{9604}{x^2}

\Rightarrow x^3=\frac{9604}{28}

\Rightarrow x=7

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C''|_{x=7}= 28+\frac{19208}{7^2}>0

Since at x=7, C''>0, So at x=7 , The cost of material will be minimum.

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Therefore the dimension of box is 7 ft by 7 ft by 14 ft.

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                                             =$2,058

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