<u>Answer:</u> The average percent yield of MgO is 98.59 %.
<u>Explanation:</u>
The chemical equation follows:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of Mg = 0.411 g
Molar mass of Mg = 24.3 g/mol
Plugging values in equation 1:
By the stoichiometry of the reaction:
If 2 moles of Mg produces 2 moles of MgO
So, 0.0170 moles of Mg will produce = of MgO
We know, molar mass of = 40.3 g/mol
Putting values in equation 1, we get:
The percent yield of a reaction is calculated by using an equation:
......(2)
Given values:
Actual value of the product = 0.675 g
Theoretical value of the product = 0.685 g
Plugging values in equation 1:
Hence, the % yield of the product is 98.54 %
Given mass of Mg = 0.266 g
Molar mass of Mg = 24.3 g/mol
Plugging values in equation 1:
By the stoichiometry of the reaction:
If 2 moles of Mg produces 2 moles of MgO
So, 0.011 moles of Mg will produce = of MgO
We know, molar mass of = 40.3 g/mol
Putting values in equation 1, we get:
The percent yield of a reaction is calculated by using an equation:
......(2)
Given values:
Actual value of the product = 0.437 g
Theoretical value of the product = 0.443 g
Plugging values in equation 1:
Hence, the % yield of the product is 98.64 %
Average of a measurement is calculated by given formula:
where,
= percentage yield for Trial 1 = 98.54 %
= percentage yield for Trial 2 = 98.64 %
Putting values in above equation, we get:
Hence, the average percent yield of MgO is 98.59 %.