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Vinil7 [7]
3 years ago
9

What is the nonpermissible value of x in 5x/6x+3

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer: -\frac{1}{2}

<u>Step-by-step explanation:</u>

\frac{5x}{6x+3}

Restriction: 6x + 3 ≠ 0     <em>denominator cannot be zero</em>

                   <u>     -3  </u>  <u> -3 </u>

                    6x      ≠ -3

                 <u> ÷6       </u>   <u>÷6 </u>

                      x       ≠ -\frac{1}{2}

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
Someone should help me out please​
Maurinko [17]

Answer:

18 in

Step-by-step explanation:

First you would multiply 2·5=10 then for the area of the bottom shape you already have 4 for one side to get the other side you subtract 7-5 and get 2 so 4·2=8 so then add the areas of both shapes and get 18

4 0
3 years ago
Suppose f(x)=x^2-2 find the graph of f(1/2x)
Scorpion4ik [409]

Answer:

graph g(x)=1/4 x^2 - 2

Step-by-step explanation:

You are to replace x with (1/2x) in the expression x^2-2

So you have (1/2x)^2-2

1/4 x^2-2

Graph some points for g(x)=1/4 x^2-2

The vertex is (0,-2) and the parabola is open up.

I would graph 2 more points besides the vertex

x   |  g(x)                     ordered pairs to graph

-----------                         (-1,-1.75) and (0,-2) and (1,-1.75)

-1        -1.75

0         -2

1         -1.75

3 0
2 years ago
Read 2 more answers
Urgent, please i will give brainliest
Ne4ueva [31]

Answer:

1. \frac{\sqrt{13} }{3}

2. 3.2362

3. \frac{60}{11}

Step-by-step explanation:

1.

Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>

By pythagorean theorem, we have the "hypotenuse" as  \sqrt{2^2+3^2}=\sqrt{13}

Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc \theta = \frac{\sqrt{13} }{3}</em>

<em />

<em>First answer choice is right.</em>

<em />

2.

By definition, Csc \theta is the inverse of Sine \theta. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Csc\theta=\frac{1}{0.3090}\\=3.2362

Third answer choice is right.

3.

By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

Cot\theta=\frac{60}{11}

Third answer is right.

3 0
3 years ago
Read 2 more answers
Draw a line representing the rise and a line representing the run of the line State the slope of the line in simplest form
amid [387]
Slope is -5/3
I hope this helps :)

8 0
3 years ago
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