<h2>
Answer with explanation:</h2>
Given : A store owner claims that the proportion of shoppers who use coupons is less than 25%.
Then , the null hypothesis and the alternative hypothesis will be :-
, since the alternative hypothesis is left tailed , so the test is a left tailed test.
Also,t the test statistic for this hypothesis test is −1.17 and the critical value for this hypothesis test is −1.282 .
We know that when the test statistic value if greater than the critical value , then we reject the null hypothesis.
Here test statistic value(−1.17 ) is greater the critical value(−1.282) for this hypothesis , so we reject the null hypothesis.
So we conclude that there is enough evidence to support the claim.
Making less money in today’s dollars (option c)
Answer:
0.533
Step-by-step explanation:
Answer:
a. 0.93 b. 0.06 c. 0.05
Step-by-step explanation:
Probability is commonly known as the chance of success of a particular event. The probability of failure of the event can also be estimated.
(a) Probability of not having type 2 defect is:
= 1 - 0.07 = 0.93
(b) Probability of having type 1 and 2 defects is: ![P(A_{1} n A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1}U A_{2}) = 0.12 + 0.07 - 0.13 = 0.06](https://tex.z-dn.net/?f=P%28A_%7B1%7D%20n%20A_%7B2%7D%29%20%3D%20P%28A_%7B1%7D%29%20%2B%20P%28A_%7B2%7D%29%20-%20P%28A_%7B1%7DU%20A_%7B2%7D%29%20%3D%200.12%20%2B%200.07%20-%200.13%20%3D%200.06)
(c) probability pf having both type 1 and type 2 defects but not type 3 defect is:
![P(A_{1} + A_{2} + A^{'} _{3}) = P(A_{1} n A_{2}) - P(A_{1} n A_{2} n A_{3}) = 0.06 - 0.01 = 0.05](https://tex.z-dn.net/?f=P%28A_%7B1%7D%20%2B%20A_%7B2%7D%20%2B%20A%5E%7B%27%7D%20_%7B3%7D%29%20%3D%20P%28A_%7B1%7D%20n%20A_%7B2%7D%29%20-%20P%28A_%7B1%7D%20n%20A_%7B2%7D%20n%20A_%7B3%7D%29%20%3D%200.06%20-%200.01%20%3D%200.05)
Answer:
240 students
Step-by-step explanation:
Grade 7 : Grade 8 = 5 : 3
Number of seventh grade students = 5x
Number of Eighth grade students = 3x
3x = 90
x = 90÷3
x = 30
Total students = 5x + 3x = 8x = 8 * 30 = 240