In mathematics, the irrational numbers are all the real numbers which are not rational numbers, the latter being the numbers constructed from ratios of integers.
Answer:
76
Step-by-step explanation:
n a competitive exam of 40 questions, +3 is awarded for a correct answer and -1 for every wrong answer. Find the total score if a student had 11 wrong answers in his attempt of all questions.
Answers gotten wrong = 11
answers gotten right = 40 - 11 = 29
total score = (point for correct answer x number of correct answer) + (point for wrong answer x number of wrong answer)
(+3 x 29) + (-1 x 11) = 76
Answer:
base : 30 cm
height : 20 cm
perimeter : 92 cm
Area : 400 cm
Step-by-step explanation:
base : 30 cm
height : 20 cm
perimeter : 27 + 30 + 25 + 10
: 92 cm
Area : (1/2 ( a + b) ) x h
: (1/2 ( 10 + 30) ) x 20
: (20) x 20
: 400 cm
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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