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3 years ago

Nth term for quaratic sequence -7,-6,-3,2,9,18,29

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

-7, -6, -3, 2, 9, 18, 29, 42, 57

Rule: + 1, + 3, + 5, + 7, + 9, + 11, + 13, + 15, + 17......................

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Ian has the option of purchasing or renting a home. The purchase option requires a loan of $100,000 for a 20-year term at a 4.9%

jenyasd209 [6]

Answer:

The correct answer to the following question will be "70.56".

Step-by-step explanation:

The given values are:

Loan requires, PV = $100,000

Years = 20

Number of months, n = 240

Rate interest = 4.90000%

Monthly rate, r = 0.408333%

Monthly rental payment = $725

As we know,

$PV=PMT\times (\frac{1}{r})\times [1-[\frac{1}{(1+r)^n}]]$

On putting the values in the above formula, we get

⇒ $100000=PMT\times (\frac{1}{0.004083333})\times [1-(\frac{1}{(1+0.004083333^{240})})]$

⇒ $100000=PMT\times 152.8014557$

⇒ $PMT=\frac{100000}{152.8014557}$

⇒ $PMT=654.44$

Now,

$Saving \ Per \ Month =Rent \ per \ month-PMT$

On putting the values, we get

⇒ $=725-654.44$

⇒ $=70.56$

3 0

3 years ago

PLZ HELP 20 POINTS

katrin2010 [14]

Can you tell us what the statement is and what we have to fill in please?

7 0

3 years ago

Read 2 more answers

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago

HELP PLEASE!!!!!!! Asap Giving out brainliest!<br> Which of the following has the greatest value?

Jlenok [28]

1/3^-2

You flip the denominator and the numerator to make the 3^-2 positive.

3^2/1= 3^2= 9

1/2^-3

2^3/1= 2^3= 8

I can already tell you that the negative exponents are not going to be as high in value.

3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8

1/3^-2 (the first option) <=== the highest in value

I hope this helps!
~kaikers

6 0

3 years ago

PLS HELP ASAP<br><br> Which number is less? 3/5 OR 0.53

kotykmax [81]

Answer:

0.53

Step-by-step explanation:

53/100<60/100

3 0

2 years ago

Read 2 more answers