We can think of this as a right triangle, where the given lengths are the legs.
So, we can solve using the Pythagorean Theorem.
21² + 28² = c²
441 + 784 = c²
1225 = c²
35 = c
35 miles
9514 1404 393
Answer:
3x -4y = -9
Step-by-step explanation:
Multiply by 4 to clear the fraction.
4(y -6) = 3(x -5)
Subtract the left-side term to get variables on the same side, with a positive x-coefficient.
0 = 3(x -5) -4(y -6)
Eliminate parentheses and collect terms.
0 = 3x -15 -4y +24
0 = 3x -4y +9
Subtract 9 and swap sides to get standard form.
3x -4y = -9
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Standard form is ...
ax +by = c
where a ≥ 0, and a, b, c are mutually prime integers. If a=0, then b > 0.
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The attached graph shows the equations give the same line. The original line is shown dotted so that you can see they overlap.
Answer:
-1.25
Step-by-step explanation:
Better to write this as
a(n)= -5(1/2)^(n-1)
Then the 3rd term is a(3) = -5(1/2)^(3 - 1), or a(3) = -5(1/2)^2 = -5/4 = -1.25
Answer:
1.We say a coin is fair if it has probability 1/2 of landing heads up and probability 1/2 of landing tails up. What is the probability that if we flip two fair coins, both will land heads up? It seems plausible that each should be equally likely. If so, each has probability of 1/4.
2.The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25.
3.his states that the probability of the occurrence of two mutually exclusive events is the sum of their individual probabilities. As you can see from the picture, the probability of getting one head and one tail on the toss of two coins is 0
Step-by-step explanation:
