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KonstantinChe [14]
3 years ago
14

Graph the line passing through the given point and having the given slope (0,3), m=4

Mathematics
1 answer:
andriy [413]3 years ago
3 0

<u>Hint </u><u>:</u><u>-</u>

  • To find out the equation of the line we can use the point slope form of the line which is y - y_1 = m(x-x_1)

<u>Solution</u><u> </u><u>:</u><u>-</u>

The given point to us is , (0,3) and the slope of the line is 4 . On using the point slope form , we have ,

\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}

<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>

( for graph , see attachment ) .

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The equation is missing 't' terms. The correct equation is:

h=-16t^2+126t

Answer:

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Step-by-step explanation:

Given:

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h=-16t^2+126t

(a)

At maximum height, the speed of the ball is 0 momentarily. Speed is nothing but rate of change of height which is the first derivative of height with time. Therefore,

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Now, maximum height is obtained by plugging in t=3.9375. Thus,

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Therefore, the maximum height of the ball is 248.06 ft. (Rounded to nearest hundredth)

(b)

Now, total time of travel of the ball is the sum of time taken to reach maximum height and the time taken from maximum height to the bottom.

Also, time taken for upward journey would be same as that of downward journey. Therefore, total time taken is twice that of the upward journey.

We have,

Time to reach maximum height, t = 3.9375\ s

Therefore, total time the ball was in air = 2(t)=2\times 3.9375=7.875\ s

Hence, the ball was in the air for 7.88 s. (Rounded to nearest hundredth)

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