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KonstantinChe [14]
2 years ago
14

Graph the line passing through the given point and having the given slope (0,3), m=4

Mathematics
1 answer:
andriy [413]2 years ago
3 0

<u>Hint </u><u>:</u><u>-</u>

  • To find out the equation of the line we can use the point slope form of the line which is y - y_1 = m(x-x_1)

<u>Solution</u><u> </u><u>:</u><u>-</u>

The given point to us is , (0,3) and the slope of the line is 4 . On using the point slope form , we have ,

\implies y - y_1= m(x-x_1) \\\\\implies y-3 = 4(x-0) \\\\\implies y -3 = 4x \\\\\implies \boxed{ 4x - y + 3 =0}

<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>

( for graph , see attachment ) .

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We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

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