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Iteru [2.4K]
3 years ago
8

I'm reallly confused on how to solve this. I know that I need to find the whole though. If you answer this, please give me an ex

planation if you know the answer. Thank You.

Mathematics
1 answer:
romanna [79]3 years ago
7 0

Answer:

hellp

Step-by-step explanation:

help

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Can someone pls help me
NeX [460]

Answer:34 1/2 cubes can fit

   

Step-by-step explanation: multiply all of them by 2

3 0
3 years ago
Y=-x-3
nadya68 [22]

Answer: Heyaa! :)

  • <em>1. y=-x-3 = -1</em>

<em>Slope:  </em>−1

<em>y-intercept: </em>(0,−3)

  • <em>2. y=4x-5 =</em> 4

<em>Slope:</em> 4

<em>y-intercept: </em>(0,−5)

  • <em>3. 2x-y=-2 =</em> 2

<em>Slope:</em> 2

<em>y-intercept:</em> (0,2)

  • <em>4. x+y=4 =</em> 1

Slope: −1

<em>y-intercept:</em> (0,4)

  • <em>5. 3x+4y=-12 = - 3/4</em>

<em>Slope: </em>−3/4

<em>y-intercept: </em>

(0,−3)

Hopefully this helps<em> you!</em>

<em />

- Matthew

4 0
2 years ago
9/17 15/34 6/17 9/34 geometric sequence?
zysi [14]
In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

9/17 = 18/34
15/34
6/17 = 12/34
9/34

Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.

This would match the definition of an arithmetic sequence and NOT a geometric sequence.
6 0
3 years ago
Complete the table and sketch the graph​
Simora [160]

Answer:

where's the picture?

Step-by-step explanation:

can I have the pic po

4 0
2 years ago
Write the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5)
Sedbober [7]

Answer:   \bold{y=-\dfrac{1}{3}x-1}

<u>Step-by-step explanation:</u>

(4, 1) & (2, -5)

First, find the slope (m) and then the perpendicular (opposite reciprocal) slope:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\\m=\dfrac{-5-1}{2-4} = \dfrac{-6}{-2}=3\quad \rightarrow \quad m_{\perp}=-\dfrac{1}{3}\\

Next, find the midpoint of (4, 1) and (2, -5):

Midpoint=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{4+2}{2},\dfrac{1-5}{2}\bigg)\\\\\\.\qquad \qquad=\bigg(\dfrac{6}{2},\dfrac{-4}{2}\bigg)\\\\\\.\qquad \qquad=(3, -2)

Lastly, input the perpendicular slope and the midpoint into the Point-Slope formula to find the equation of the line:

y - y_1 = m_{\perp}(x - x_1)\\\\y - (-2) = -\dfrac{1}{3}(x - 3)\\\\y + 2=-\dfrac{1}{3}x +1\\\\y =-\dfrac{1}{3}x - 1\\


6 0
2 years ago
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