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KIM [24]
3 years ago
9

Gary has twice as many m&ms as larry. Jerry has three times as many m&ms as larry. Together the tree men have 108 m&

ms. How many m&ms does gary have?
Mathematics
1 answer:
Igoryamba3 years ago
5 0

Answer:

36

Step-by-step explanation:

Let number of m&ms Garry has be g

number of m&ms Larry has be l

Number of m&ms Jerry has be j

Since Gary has TWICE as Larry, we can write:

g = 2l

Also, Jerry has THRICE as Larry, we can write:

j = 3l

Together, they have 108, thus, we can write:

g + l + j = 108

Putting 1st and 2nd equation in 3rd, we can solve for Larry first. Shown below:

g + l + j = 108\\2l+l+3l=108\\6l=108\\l=\frac{108}{6}\\l=18

Larry has 18. To find Gary's number, we can use the fact g = 2l, so

g = 2 * 18 = 36

Gary has 36 m&ms

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Dave buys a baseball catchers equipment for $295. The tax rate is 7.9%. How much tax did Dave pay? Round your answer to the near
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3 years ago
Lydia bought 2 ½ gallons of paint and used 1 ½ gallons of paint. What fraction of the paint did she use?
grandymaker [24]
3/5 is used

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Please find the SURFACE AREA of this figure... Write the formula and plug in the values... Write your answer with units and box
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124(cm)^2

Step-by-step explanation:

total surface area of a cuboid=2(LB+BH+HL)

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5 0
3 years ago
The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri
VARVARA [1.3K]

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

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⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ AD^{2} + BD^{2} = AB^{2}

⇒AD^{2} =AB^{2} - BD^{2}

⇒AD^{2} =6^{2} -3^{2}

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⇒AD = \sqrt{25}

⇒AD = 5 inches

6 0
3 years ago
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