What is the perimeter of a rectangle with an area of 2x^2+11x+5 in^2?

Mathematics

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

6x + 14

Step-by-step explanation:

Area = side x side

Factor the quadratic:

2x^2 +10x / +1x +5

2x(x+5) 1 (x+5)

(2x + 1) (x+5)

^These are your two sides

Perimeter =2L + 2W

(2(2x+1)) + (2(x+5))

4x+4+2x+10 = final answer 6x + 14

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the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta

Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

$AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units$