What is the perimeter of a rectangle with an area of 2x^2+11x+5 in^2?
1 answer:
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The values are and
Explanation:
From the figure, we can see that the two quadrilaterals are similar.
Thus, by the property of quadrilateral, for similar quadrilaterals, their corresponding angles and sides are congruent. Thus, we have,
∠D = ∠S, ∠E = ∠P, ∠G = ∠R and ∠F = ∠Q
Also, GF = QR and DE = PS
Where QR = and ∠D = 102°, ∠G = 84° and ∠F = 68°, ∠Q =
°
Hence, to determine the value of x for the side QR, we have,
Equating the values in GF = QR,we get,
Thus, the value of x is 8.
Substituting x in the angle Q to determine the value of y.
Thus, we have,
∠F = ∠Q
Thus, the value of y is 10.
Hence, The values are and
Answer:
Length of the rectangle = 16 inches
Width of the rectangle = 12 inches
Step-by-step explanation:
Let the length of the rectangle be represented by x.
Then width can be expressed as
Perimeter of a rectangle is the sum of four sides of the rectangle.
This can be expressed as 2*(length + breadth)
=
=
=
But perimeter is given as 56.
So,
=>
=>
Hence length of the rectangle = 16 inches
Width of the rectangle = = 12 inches
Answer:
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