Determine the volume of a cylindrical bucket if the diameter is 8.5 in. and the height is 11.5 in.

1 answer:

7 0

The volume of the cylinder is πr2h
So we have ,
Height:11.5in
Diameter:8.5in
Radius=8.5/2
Now from the above information,
Volume = πr2h
= 22/7x8.5/2x8.5/2x11.5
Cancelling 2and 22 ,we get,
=11/7x8.5x4.25x11.5 (as we divided 8.5/2)
=1.57x8.5x4.25x11.5
=652.2in3
HOPE IT WAS HELPFUL :)

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Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160

s344n2d4d5 [400]

Answer:

C. $130^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc $CD = 40^o$ , arc $AB = 60^o$ , and arc $BC = 160^o$ . We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.

$\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}$