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I am Lyosha [343]
3 years ago
10

3/12 and 5/x are equivalent ratios. Solve for X. Pls help asap

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

3/12  and 5/x

12 times 5 is 60 so 3 times 20 shall be 60

3/12 = 5/20

:)

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julsineya [31]
The tree is 7.5ft because it's shadow is half it's height.
5 0
3 years ago
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2+1.25f=10−2.75f solve for f
Inga [223]
Hey there!

2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.

1.25f + 2.75f = 4f

4f + 2 = 10
Subtract 2 from both sides.

4f = 8
Divide both sides by 4 to solve for f.

f = 2

I hope this helps!
6 0
4 years ago
Write an equation in point-slope form of the line that passes through the point (5, 6) with slope 3/5​
I am Lyosha [343]

Answer:

(y - 6) = 3/5(x - 5)

Step-by-step explanation:

First, let's look at what point-slope form is: (y - y₁) = m(x - x₁)

Let's plug in the vallues we know.

m is the slope: 3/5

x₁ is 5

y₁ is 6

Therefore:

(y - 6) = 3/5(x - 5)

This is your equation.

Hope this helps!

8 0
3 years ago
State a number that would lie between -2.15 and -2.16 on the number line
Aleks04 [339]

Answer:

One answer would be -2.155.

3 0
3 years ago
Read 2 more answers
Activity: A flagpole has cracked 1.7 m from the ground and fallen over, as if hinged. The top of the flagpole hit the ground 3 m
Anastasy [175]

Answer:

Height of flagpole before it fell = 5.15 m

Step-by-step explanation:

Given:

Height of remain pole (p) = 1.7 m

Distance from base (b) = 3 m

Find:

Height of flagpole before it fell

Computation:

Using Pythagorean theorem

H = √ p² + b

Length of broken part = √ 1.7² + 3²

Length of broken part = √ 2.89 + 9

Length of broken part = √ 11.89

Length of broken part = 3.45 (Approx)

Height of flagpole before it fell = Length of broken part + Height of remain pole

Height of flagpole before it fell = 3.45 + 1.7

Height of flagpole before it fell = 5.15 m

8 0
3 years ago
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