You're given the slope of the line and a point thru which the line passes. So it makes sense to use the point-slope form of the equation of a straight line: if the point is (a,b) and the slope is m, then
y-b=m(x-a). You'd then solve this for y to obtain the equation in slope-intercept form.
On the other hand, if you're asked to write the equation in slope-intercept form, starting with the general form of this equation may be faster: y=mx+b.
Substitute the given values for x and y (which are 25 and -9) and m (which is (2/5). Solve the resulting equation for b (the y-intercept).
Then write the finished equation: y=( ? )x + b, where b is the y-intercept you've just found.
Standard Equation for trig function: y = A cos (B (x - H))+ K
*Here, we are just dealing with A (amplitude) and B (period)
Period = 2π/ b
8 = 2π/ b
Solve for b: 2π/8 or π/4
Equation: y = 2 cos (π/4 (x))
Answer:
<u><em>0-20</em></u>
Step-by-step explanation:
Answer:
sure whats the question
Step-by-step explanation:
