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QveST [7]
3 years ago
8

PLEASE HELP IM ON A TIME LIMIT :(

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

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\text{I hope this helps, have a good day.}

3 0
3 years ago
LOTS OF POINTS!!! PLEASE ANSWER IT
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a) C

b) F

c) A

d) D

e) B

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So, T ⇒ n+2

For table b)

The values of T is 3 less than the values of n

So, T ⇒ n-3

For table c)

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So, T ⇒ 3n

For table d)

The values of T is 2 more than from the thrice of the values of n

So, T ⇒ 3n+2

For table e)

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For table f)

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