<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
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<h3>Answer:</h3><h3>72 </h3><h3>Step-by-step explanation:</h3><h3>form the table it is shown that 5 was skipped to 6 </h3><h3>so to get term 5 </h3><h3> we say if 48-36=12 and 36-26=12 ......in A.P series </h3><h3>so the difference is 12 </h3><h3>therefore the 5th term is 48+12 = 60 </h3><h2>and 6th term is 60+12= 72 </h2>
Answer: x<4
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
x+3<7
Step 2: Subtract 3 from both sides.
x+3−3<7−3
x<4