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Ahat [919]
2 years ago
14

Paul's rule is "square, triangle, circle." How can Paul find the seventeenth shape?

Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

1. keep counting

2. He can do 5 times 3 to get to the 15th shape and then say 2 more to get the 17th shape.

(The 17th shape would be triangle)

Savatey [412]2 years ago
7 0
Square is the right one, hope this helps
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Need help with this problem explain pls
Usimov [2.4K]
All sides of an equilateral triangle are equal, so all three sides are 9 cm.
To find h, use the pythagorean theorem. This requires use of only one right triangle, where we use b as our h.

a^2+b^2=c^2
(4.5)^2+b^2=(9)^2
(20.25)+b^2=(81)
b^2=(81/20.25) or 4
square root both sides
b=2
6 0
3 years ago
Solve the equation 12+ 0.35×=20.05
lbvjy [14]
12 + 0.35X = 20.05
12 + 0.35X - 12 = 20.05 - 12
0.35X = 8.05 
0.35X/0.35 = 8.05/0.35
X = 23
Hope this helps!! 
8 0
3 years ago
If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw
serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

\text{Depreciation rate}=\frac{15000+7000}{5}

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0
3 years ago
Find the first four terms for the arithmetic sequence given a1 = 6 and d = 5
DENIUS [597]

Answer:

6, 11, 16, 21

Step-by-step explanation:

To obtain the first 4 terms add the common difference 5 to the previous term, that is

a₁ = 6

a₂ = a₁ + 5 = 6 + 5 = 11

a₃ = a₂ + 5 = 11 + 5 = 16

a₄ = a₃ + 5 = 16 + 5 = 21

7 0
3 years ago
Which quadratic inequality does the graph below represent?
sergejj [24]

Answer:

y< or equal to x^2-3.

I hope it helps.

4 0
2 years ago
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