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Ahat [919]
2 years ago
14

Paul's rule is "square, triangle, circle." How can Paul find the seventeenth shape?

Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

1. keep counting

2. He can do 5 times 3 to get to the 15th shape and then say 2 more to get the 17th shape.

(The 17th shape would be triangle)

Savatey [412]2 years ago
7 0
Square is the right one, hope this helps
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a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
4 years ago
Find the value of x.
slavikrds [6]

Answer:

x=11

Step-by-step explanation:

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

so

In this problem

(x+5)=\frac{1}{2}(3x-1)

solve for x

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2x+10=3x-1

subtract 2x both sides

10=3x-1-2x

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Adds 1 both sides

x=11

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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