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aleksandr82 [10.1K]
3 years ago
13

Write an equation of a line with the given slope and y-intercept. m = , b = 2

Mathematics
1 answer:
Vlad [161]3 years ago
3 0

Answer:

<u>Equation</u><u> </u><u>is</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>mx</u><u> </u><u>+</u><u> </u><u>2</u>

Step-by-step explanation:

General equation of line:

{ \boxed{ \bf{y = mx + b}}}

Substitute in considerance of the question:

{ \sf{ y = mx + 2}}

If m is given, substitute for m to the answer.

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Hi! I need help with this:
arlik [135]
<h3>Answer:  50</h3>

==========================================================

Explanation:

We simply multiply the two values given to us

600*(1/12) = 600/12 = 50

We expect about 50 bulbs to be defective.

Note how if we had 50 bad bulbs, then 50/600 = (1*50)/(12*50) = 1/12 of the batch of 600 bulbs is defective.

5 0
3 years ago
Find the volume of a cube 8 1/8 cm.
DedPeter [7]
V=a^3
V=8 1/2^3
V=614.125
8 0
3 years ago
Read 2 more answers
Like b and c are parallel what is the measure of &lt;2
Vadim26 [7]
C
Hope this helps 8)
5 0
3 years ago
John put away 36 of 48 shirts in his closet. Don has 84 shirts. If he put away the same percent, how many shirts did Don put in
Alexeev081 [22]

Answer:

63

Step-by-step explanation:

John's percentage:

36 and 48 have a common factor of 12 so divide both of them by 12.

36/12= 3 and 48/12=4 therefore

so 36/48= 3/4 which is 75% but we don't need to focus on the percent.

Don's no. of shirts:

we know Don has 84 shirts so we say

3/4 of 84= no. of shirts that Don put in his closet

84/4=21 21x3=63

Don put 63 shirts in his closet.

Hope that helped! Anymore questions just ask! :)

3 0
3 years ago
Please help fast.
podryga [215]

\huge{\underline{\boxed{\tt{Answer:}}}}

Let AB be a chord of the given circle with centre and radius 13 cm.

Then, OA = 13 cm and ab = 10 cm

From O, draw OL⊥ AB

We know that the perpendicular from the centre of a circle to a chord bisects the chord.

∴ AL = ½AB = (½ × 10)cm = 5 cm

From the right △OLA, we have

OA² = OL² + AL²

==> OL² = OA² – AL²

==> [(13)² – (5)²] cm² = 144cm²

==> OL = √144cm = 12 cm

Hence, the distance of the chord from the centre is 12 cm.

━═━═━═━═━═━═━═━═━━═━═━═━═━═━

8 0
3 years ago
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