A rectangle has a height of 5y; and a width of 3y3

mrs jacobson asks each group of students to write an expression equivalent to the model shown. which group is incorrect expressi

madreJ [45]

Where is the model. To answer I need the model.

8 0

3 years ago

Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

antoniya [11.8K]

The perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

<h3>What a quadrilateral?</h3>

A quadrilateral is simply a polygon with four sides, four angles, and four vertices.

To get the perimeter, we simply add the values of the four side.

Given that;

The vertices are at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

To get the dimension between the given coordinates, we use;

d = √((x2 -x1)² +(y2 - y1)²)

For length CD, DE, EF and FC

CD = √((2 - (-2))² + (4 - 1)²) = √( 16+9) = √25 = 5

DE = √((5 - 2)² + (0 - 4)²) = √( 9+16) = √25 = 5

EF = √((1 - 5)² + (-3 - 0)²) = √( 16+9) = √25 = 5

FC = √((-2 - 1)² + ( 1 - (-3))²) = √( 9+16) = √25 = 5

Perimeter of the quadrilateral = CD + DE + EF + FC

Perimeter of the quadrilateral = 5 + 5 + 5 + 5

Perimeter of the quadrilateral = 20units

Therefore, the perimeter of the quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3) is 20units.

Option C) is the correct answer.

Learn more about area of rectangle here: brainly.com/question/27612962

#SPJ1

6 0

2 years ago

Read 2 more answers

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, $A +B+C+D = 5+6-10+2 = \bold3$

5 0

3 years ago

PLZ HELP THIS IS DUE SOON!!!!!!! Divide. Round to the nearest hundredth if necessary.

ivolga24 [154]

Answer:

10

Step-by-step explanation:

when you divide 80.88 by 8.425 you get 9.6

and since youre rounding, you can round up 6 because its higher than 5

and your final answer should be 10.

hoped this helped! :)

4 0

3 years ago

What is an equation of the line that passes through the points (0, 3) and (5,-3)?

Arisa [49]

Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

$y = m\cdot x + b$ (Eq. 1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $(x_{1},y_{1}) = (0,3)$ and $(x_{2},y_{2})=(5,-3)$ , the following system of linear equations is constructed:

$b = 3$ (Eq. 2)

$5\cdot m + b = -3$ (Eq. 3)

The solution of the system is: $b = 3$ , $m = -\frac{6}{5}$ . Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

5 0

3 years ago

A rectangle has a height of 5y; and a width of 3y3 – 8y2 + 2y.