AB = Round your answer to the nearest hundredth. 5 C А 65° B

Mathematics

1 answer:

Snezhnost [94]2 years ago

4 0

Answer:

$AB = 5.52$

Step-by-step explanation:

Reference angle = 65°

Opposite side = 5

Hypotenuse = AB = ?

To find AB, the trigonometric ratio we would use will be:

$sin(\theta) = \frac{opp}{hyp}$

Plug in the values

$sin(65) = \frac{5}{AB}$

Cross multiply

$sin(65)*AB = 5$

Divide both sides by sin(65)

$AB = \frac{5}{sin(65)}$

$AB = 5.52$ (nearest hundredth)

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4j + 4 = Next, subtract 4 from both sides. 4j

WINSTONCH [101]

Answer:

4j=-4

j=-1

Step-by-step explanation:

5 0

2 years ago

Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.

irina1246 [14]

Lagrange multipliers:

$L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)$

$L_x=y^2z^2+\lambda=0$
$L_y=2xyz^2+\lambda=0$
$L_z=2xy^2z+\lambda=0$
$L_\lambda=x+y+z-5=0$

$\lambda=-y^2z^2=-2xyz^2=-2xy^2z$

$-y^2z^2=-2xyz^2\implies y=2x$ (if $y,z\neq0$ )

$-y^2z^2=-2xy^2z\implies z=2x$ (if $y,z\neq0$ )

$-2xyz^2=-2xy^2z\implies z=y$ (if $x,y,z\neq0$ )

In the first octant, we assume $x,y,z>0$ , so we can ignore the caveats above. Now,

$x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2$

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of $f(1,2,2)=16$ .

We also need to check the boundary of the region, i.e. the intersection of $x+y+z=5$ with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force $f(x,y,z)=0$ , so the point we found is the only extremum.