Ask question

Ask question

All categories

2 years ago

8

Martha measures the big prize wheel on a game show and calculates that it has a circumference of 12.56 yards. What is the prize

wheel's radius?

1 answer:

trasher [3.6K]2 years ago

7 0

The radius is 2 yards...
Formula for circumference is $\pi r^2$ so divide your circumference by 3.14 or pi and you get 4 the square root of 4 is 2.

Hope this helps!

You might be interested in

Explain how to determine the zeros of f(x)= (x+3)(x-2)(x-6)

Deffense [45]

Answer:

The zeros of f(x) are -3, 2 , 6

Step-by-step explanation:

f(x) is a polynomial of degree 3.

If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.

Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.

f(x) = (x+3)(x-2)(x-6)

x + 3 = 0 => x = -3

x - 2 = 0 => x = 2

x - 6 = 0 => x = 6

8 0

2 years ago

Mai biked 6\frac{3}{4} miles today, and Noah biked 4\frac{1}{2} miles.

Alinara [238K]

It was 1.5 times the length of Noah's bike ride as Mai’s bike ride.

The problem we dealing with is related to mixed numbers which are referred to as mixed numbers and could be the whole number, and a proper division spoke together. It for the most part speaks to a number between any two whole numbers.

Since we are providing mai's rate which is 6 3/4 miles and Noah's rate of 4 1/2 miles, So in order to find the time the length of Noah's ride is compared to Mal's, we just need to divide the given rates by each other

=> 6 3/4 divided by 4 1/2,

=> 27/4 divided by 9/2, (The result is an improper fractions)

=> 27/4 X 2/9

=>3/2

=> 1.5

To know more about mixed numbers refer to the link brainly.com/question/24137171?referrer=searchResults.

#SPJ1

3 0

7 months ago

Need help solving this problem

ANTONII [103]

Here is the solution for the eqns.

6 0

3 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

The diagonal of the floor of a square room is 6 meters.what is the length of a side of the room? round to the nearest tenth.

shutvik [7]

Side of the room = x.
From the right triangle, where sides of the square are legs of the right triangle, and the diagonal of the square is a hypotenuse of the right triangle.
x²+x²=6²
2x²=36
x²=18
x=√18 =√(2*9)=3√2≈4.2m

4 0

3 years ago