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3 years ago

Please help. due today.

Mathematics

1 answer:

guapka [62]3 years ago

3 0

Answer:

1, 1/2, 1 1/2

Step-by-step explanation:

Question 1

20 divided by 18 is 1.1

So the answer is closest to 1

Question 2

9 divided by 20 is 0.45

So the answer is closest to 1/2

Question 3

7 divided by 5 is 1.4

So the answer is closest to 1 1/2

Hope this helps!

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Which equation could be the equation of this parabola?

grin007 [14]

D, Because the equation must be in slope intercept (y=mx+b) and since it is going upwards (all positive nunbers) then the slope would be positive as well. I hope this helps!

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3 years ago

Read 2 more answers

What is an example of a non linear graph?

Xelga [282]

With the exception of the form f(x) = ax + b, non-linear graph equation can take any form.See graph in photo attached.

<h3>What is non linear function and its graph?</h3>

As the name suggests, a nonlinear function is one that is NOT linear.

To put it another way, a nonlinear function's graph is not a linear. In other words, its graph is not limited to being a line.

Any function whose graph is not a straight line should be considered a nonlinear function since a nonlinear function is one that is NOT linear.

Since none of the graphs in the following figure are straight lines, they all illustrate nonlinear functions.

Learn more about non-linear graph here:

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2 years ago

100 x 54 + 77 ÷ 2 = ? (RIGHT ANSWER GETS BRAINLIEST)

Nadusha1986 [10]

Answer:

5438.5

Step-by-step explanation:

To complete this equation, we must use the order of operations also known as PEMDAS.

For the case of this problem, we start by multiplying or dividing numbers before adding or subtracting numbers.

First let's start on the left:

100 x 54 + 77 ÷ 2

5,400 + 77 ÷ 2

5,400 + 38.5

5438.5

I hope this helps! Just remember to always add or subtract number last and start on the left, so that you don't get confused.

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3 years ago

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$