If you copied the "n 3" part, it's very likely that your job was to create a pattern with either the rule n^3 or n*3.
In the case of the former, we can start with the initial number of 1 and increase by 1.
In that way, using the rule n^3 would create this pattern of numbers: 1, 8, 27, 64, and so on. Or stated in another way 1*1*1, 2*2*2, 3*3*3, 4*4*4 ...
In the case of the latter, we can start with the initial number of 1 and increase it by 1.
In this way, using the rule of n*3 would create this pattern of numbers: 3, 6, 9, 12, 15, 18 and o son. Or stated in another way 1*3, 2*3, 3*3, 4*3, 5*3 ...
Answer:
y=-3x+31
Step-by-step explanation:
y-y1=m(x-x1)
y-4=-3(x-9)
y-4=-3x+27
y=-3x+27+4
y=-3x+31
Answer:
11 days
Step-by-step explanation:
first you subtract the 160 from 380 becuase thats a different part than you divide that number by 20 pages a day and end up with 11 days it took
Answer:
a = 2
Step-by-step explanation:
In an AP the difference between consecutive terms is common (equal), thus
t₂ - t₁ = t₃ - t₂ , that is
2a + 1 - (a + 1) = 4a - 1 - (2a + 1) ← distribute and simplify both sides
2a + 1 - a - 1 = 4a - 1 - 2a - 1
a = 2a - 2 ( subtract 2a from both sides )
- a = - 2 ( multiply both sides by - 1 )
a = 2
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
