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Dominik [7]
3 years ago
14

For a craft each student will need five rubber bands.There.There are eight students.Rubber bands come in bags of nine. How many

will be needed?How many rubber bands will be left over?
Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

40 rubber bands are needed

5 rubber bands will be left from 5 bags of of rubber band

Step-by-step explanation:

Each student will need five rubber bands.

There are eight students

Total rubber bands needed = rubber bands per student × number of students

= 5 × 8

= 40

Total rubber bands needed = 40

Rubber bands come in bags of nine.

Number of bags needed = Total rubber bands needed / number of rubber bands in each bag

= 40 / 9

= 4.44 bags

It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5

5 rubber bands bags will be bought which = 5 × 9

= 45 rubber bands

Only 40 rubber bands are needed

Left over rubber bands = 45 - 40

= 5 rubber bands

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5 0
3 years ago
Solve for x<br> x^2 = 65/49<br> Explain if you can too.
yuradex [85]

Answer:

I will try to solve your question

6 0
3 years ago
Read 2 more answers
Find the measures of the numbered angles.
Arte-miy333 [17]
1 = 90
2 = 65
3 = 65
4 = 25

90+25=115
180-115=65

have a merry christmas :)
3 0
2 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
2 years ago
A jet ski costs $925 and depreciates by 15% each year. How much will
ivann1987 [24]
Initial cost of the jet ski = $925
Percentage of depreciation per year = 15%
Number of years after which the cost of the jetski has to be determined = 7
Then
Depreciated Value = Initial cost( 1 - percentage of depreciation) ^number of years
                              = 925( 1 - 15%)^7
                              = 925( 1 - 15/100)^7
                              = 925(1 - 0.15)^7
                              = 925(0.85)^7
                              = 925 *(0.85)^7
                              = 925 * 0.3206
                              = 296.53 dollars
So the depreciated cost of the jet ski after 7 years will be $296.53
6 0
3 years ago
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