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Dominik [7]
3 years ago
14

For a craft each student will need five rubber bands.There.There are eight students.Rubber bands come in bags of nine. How many

will be needed?How many rubber bands will be left over?
Mathematics
1 answer:
matrenka [14]3 years ago
5 0

Answer:

40 rubber bands are needed

5 rubber bands will be left from 5 bags of of rubber band

Step-by-step explanation:

Each student will need five rubber bands.

There are eight students

Total rubber bands needed = rubber bands per student × number of students

= 5 × 8

= 40

Total rubber bands needed = 40

Rubber bands come in bags of nine.

Number of bags needed = Total rubber bands needed / number of rubber bands in each bag

= 40 / 9

= 4.44 bags

It is impossible to get decimal number of rubber bands bag, so, the next whole number after 4 is 5

5 rubber bands bags will be bought which = 5 × 9

= 45 rubber bands

Only 40 rubber bands are needed

Left over rubber bands = 45 - 40

= 5 rubber bands

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Cam was bom weighing 8.6 pounds. Every day, he gained the same amount of weight. After 30 days, he weighed 14.9
guajiro [1.7K]

Answer:

So I'm not entirely sure about this one, but I believe he gained 0.21 pounds each day for 30 days

Step-by-step explanation:

Since Cam was born weighing 8.6 pounds and after 30 days weighed 14.9, subtract 14.9-8.6 to find how much he gained.

14.9 - 8.6 = 6.3

Now that we know how much he gained, we have to find out how much he gained per day for 30 days. To do this, divide 6.3 by 30

6.3 / 30 = 0.21

To make sure this answer is correct, multiply 0.21 by 30 and add that to 8.6. It should equal 14.9.

I hope this helps!

7 0
2 years ago
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Answer: 144 meters

Step-by-step explanation: area of circle = r^2

6^2 = 36 = 144 Meters given = 4

radius of pool is 6 meters

diameter of pool is 12 meters

= 4

area of circle = r^2

area of swimming pool is 144 meters

8 0
1 year ago
The price of milk increased by 8 percent.If the original price is R10,84,what is the new price? step by step explanation
antiseptic1488 [7]

Answer:

If the price of a product decreases from $10 to $8, leading to an increase in quantity demanded from 40 to 60 units.

Step-by-step explanation:

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2 years ago
Solve by substitution. Show each step of your work.<br><br> 2x + y = 7<br><br> 3x + 5y = 14
Monica [59]
Alright...simple...showing all steps.. ;)

You have the equations...

2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28

Thus,

6x+3y=21
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6x+10y=28

=========

-7y=-7

y=1

Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....

2x+(1)=7

2x+1=7
      -1  -1

2x=6

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Thus, the point of intersection for these two equations is (3,1)
8 0
3 years ago
Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

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2 years ago
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