When solving for this problem, replace x with the first coordinate and solve. if the answer is what you have for the second, it is correct. The first number in an ordered pair is your x and the second is your y. So I would rewrite the equation like this and solve.
y=7x-19 y=7x+21
2=7(3)-19 9=7(4)-19 2=7(3)+21 9=7(4)+21
2=21-19 9=28-19 2=21+21 9=28+21
2=2 9=9 2=42 9=49
as you can see it is the first equation.
This can be solved by using the 30 60 90 triangle. The 30-60 side is equal to 2x, here it is 2x=18. The 60-90 side is equal to x. So this side is 18/2=9. The 30-90 side is by the way equal to the root of x, so here the root of 18
Answer:
Step-by-step explanation:
2x^2+8x-12=0
with form
ax^2+bx+c=0
move c to the other side
2x^2+8x=12
x^2 is multiplied -> divide equation by 2
x^2+4x=6
complete square:
divide b=4 by 2
4*1/2=2
square 2
2^2=4
add 4 to both sides
x^2+4x=6
x^2+4x+4=6+4
x^2+4x+4=10
transform to polynom
(x+2)^2=10
this left side is option B multiplied by a factor of 16 and therefore equal:
(4x + 8)^2
(4*4)x^2+(4*2*8)x+8*8
16x^2+64x+64
x^2+4+4
bonus: calculate root
x+2=+/-sqrt(10)
x=-2+/-sqrt(10)
<h2 /><h2>so it is option B</h2>
- <em>2x^2 + 8x - 12 = 0..divide by 2</em>
- <em>x^2 + 4x - 6 = 0</em>
- <em>x^2 + 4x = 6...add 4 to both sides of the equation</em>
- <em>x^2 + 4x + 4 = 6 + 4</em>
- <em>(x + 2)^2 = 10....<== ur constant is 10</em>
- <em>x + 2 = (+-)sqrt 10</em>
- <em>x = -2 (+ - ) sqrt 10</em>
- <em></em>
- <em>x = -2 + sqrt 10</em>
- <em>x = -2 - sqrt 10</em>
- <em></em>
- <em></em>
- <em></em>
Two lines that intersect and form right angles are called perpendicular lines. The symbol ⊥ is used to denote perpendicular lines.
You can solve an inequality like an equality so first for this question you should add +1 on both sides of an equation and you will have:
4x< 12 so now you should divide both sides by 4 and you will have:
x < 12/4 ⇒ x < 3 and that's the answer :))))
I hope this is helpful
have a nice day
