Answer:
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the population, we have that:
Mean = 0.5
Standard deviaiton = 0.289
Sample of 12
By the Central Limit Theorem
Mean = 0.5
Standard deviation 
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
Answer:
After 11 weeks, Darnell′s savings account will have a total of $8,360.
Step-by-step explanation:
The data provided is as follows:
n: 1 2 3 4
f (n): 260 360 460 560
Consider the data for f (n).
The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.
The nth term of an arithmetic sequence is:
![a_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Compute the value of f (11) as follows:
![f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]](https://tex.z-dn.net/?f=f%2811%29%3D%5Cfrac%7B11%7D%7B2%7D%5B%282%5Ctimes260%29%2B%2811-1%29%5Ctimes%20100%5D)
![=5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360](https://tex.z-dn.net/?f=%3D5.5%5Ctimes%5B520%2B1000%5D%5C%5C%5C%5C%3D5.5%5Ctimes%201520%5C%5C%5C%5C%3D8360)
Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.
Y=50+.05x
Just plug in the number of texts for x
y=50+.05(25)
y=51.25
^That was for 25 texts
Now just plug in all the other texts and replace that with x
Hope this helps!
10^2 is 100. 247 divided by 100 is 2.47. 2.47 + 2.47 is your answer. Im lazy, add yourself. 4.94
Answer:
See explanation
Step-by-step explanation:
Assuming you want to find the 3rd term of the geometric progression defined explicitly by
, then we have to substitute n=3 to obtain:

This will give us:

We evaluate to obtain:
