Question

In terms of x? pls solve and show your work! Will give u brainliest!

Answer 1

Answer:

$\sqrt{ {x}^{2} - 1 }$

Solution,

base=1

perpendicular=?

hypotenuse=X

now,

using Pythagoras theorem,

x^2=p^2+b^2

or, x^2=p^2+1^2

or,p^2=x^2-1

or, p=√x^2-1

tan theta=perpendicular/ base

tan theta =√x^2-1/1

tan theta=√x^2-1

z=tan theta

z=√x^2-1

Hope this helps...

Good luck on your assignment..

Answer 2

Answer:

$\sqrt{x^{2}-1}}$.

Step-by-step explanation:

The tangent of theta means that you are trying to find opposite over adjacent.

You already have the value of the adjacent (1), so all you need to do is find the opposite. That would be the square root of the hypotenuse squared minus the adjacent squared.

The opposite would be sqrt(x^2 - 1^2) = $\sqrt{x^{2}-1}}$.

When you put it together, tan(theta) = $\frac {\sqrt{x^{2}-1} }{1}$

That is $\sqrt{x^{2}-1}}$.

So, z, in terms of x, is $\sqrt{x^{2}-1}}$.

Hope this helps!