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pickupchik [31]
2 years ago
6

Question 3 of 20

Mathematics
1 answer:
olchik [2.2K]2 years ago
3 0
I think it’s C but it could be D.. i would go with C tho
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Maurice has completed 72 pages of the research paper he is writing. That is 90% of the required length of the paper. What is the
iogann1982 [59]

Answer:

its 100 pages ................

5 0
2 years ago
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Write an equation for the line parallel to y= -2x+1 that contains (-2,5)
grin007 [14]

Answer:

y = - 2x + 1

Step-by-step explanation:

Parallels line have the same slope, when an equation is in the form y= mx + b, m is the slope. In this problem slope = - 2

Now with the slope what is missing is the y-intercept, the problem says that the line contains the point (-2, 5), replacing that point in the equation you can solve it to find the y-intercept

y = mx + b

5 = (-2)(-2) + b

5 = 4 + b

1 + b

y = - 2x +1

5 0
2 years ago
Factor the trinomial. Factor out the GCF first.<br> 5x^2y - 30xy^2 - 35y^3
anzhelika [568]

Answer: 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

The given expression: 5x^2y - 30xy^2 - 35y^3

It can be written as

5x^2y - (5\times6)x( y\times y) - (5\times7)(y^2\times y)

Taking out common factor  5y , we get

5y(x^2-6xy-7y^2)\\\\ =5y(x^2+xy-7xy-7y^2)\  \ [\because-6xy=xy-7xy]\\\\=5y(x(x+y)-7y(x+y))\\\\= 5y((x+y)(x-7y))\\\\=5y(x+y)(x-7y)

Hence, 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

3 0
3 years ago
in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14
Colt1911 [192]

To show that the ratio \frac{y}{x} is not constant for the function y=a-14 we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here a represents x.  

To find the counter examples here, I will use the values a=20  and a=28. For a = 20 , the equation tells us that the output is

y=20-14=6. For this value of a the point is point is (20,6). The ratio \frac{y}{x} =\frac{6}{20}. For the a=28, y=28-14=14. For this value of a the  point is (28,14) . The ratio \frac{y}{x} =\frac{14}{28} =\frac{1}{2}. Clearly this ratio is not constant for all ordered pairs.

8 0
2 years ago
the area of a rectangle garden is 38 1/4 square meters.The width of the garden is 4 1/2 meters.Find the length of the garden.
never [62]
Area = 38 1/4 = 153/4

Width = 4 1/2 = 9/2

Area = Length x Width

Length = Area/Width

So divide both of them:
\sf{ \frac{153}{4} \div \frac{9}{2} =\sf{ \frac{153}{4} \times \frac{2}{9} = \frac{9 \times 17}{2\times 2}\times \frac{2}{9} = \frac{17}{2}

So the length is equal to \boxed{\sf{\frac{17}{2}}}

4 0
2 years ago
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