Jenny had 7 dimes and 3 pennies in her She takes a coin out from her pocket, looks at the coin and then replaces it her pocket b
efore she removes a second coin. What is
the probability she will not take out a penny both times?
F. 3/10
G. 9/100
H. 49/100
J. 21/100
1 answer:
<h3>
Answer: 49/100</h3>
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Explanation:
There are 7 dimes and 3 pennies, leading to 7+3 = 10 coins total.
The probability of not picking a penny is 7/10. If the first coin is put back, then the probability doesn't change for the second selection.
The probability of getting two dimes is (7/10)*(7/10) = 49/100 when the first coin is replaced.
If the first coin is not replaced, then the answer would be (7/10)*(6/9) = 42/90 = 7/15
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[
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