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d1i1m1o1n [39]
3 years ago
10

A manufacturer of televisions subjects the equipment to a comprehensive testing process for all essential functions before the t

elevision leaves the factory. If the probability of passing these comprehensive tests is .95 and if 10 televisions are randomly selected what is that probability that at least 9 pass the test
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

The probability is   P(X \le 9) =0.9138

Step-by-step explanation:

From the question we are told that

   The probability of the television passing the test is  p = 0.95

    The sample size is  n  =  10

Generally the comprehensive testing process for all essential functions  follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators      

    Generally the probability that at least 9 pass the test is mathematically represented as

     P(X \le 9) =  P(X = 9) + P(X = 10 )

=>  P(X \le 9) = [^{10}C_9 *  (0.95)^9 *  (1- 0.95)^{10-9}]+ [^{10}C_{10} *  {0.95}^{10} *  (1- 0.95)^{10-10}]

=> P(X \le 9) = [10 *  0.6302  * 0.05 ]+ [1 *0.5987 * 1 ]

=> P(X \le 9) =0.9138

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Answer:

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Step-by-step explanation:

(x – 2)^2 + 20 = 0

Subtract 20 from each side

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We know sqrt(ab) = sqrt(a) sqrt(b)

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