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2 years ago

7

Someone help please I need help

1 answer:

galina1969 [7]2 years ago

7 0

Answer: There all even on all sizes.

Step-by-step explanation:

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Lines y and z are parallel. what is the measure of angle 2?

Roman55 [17]

Answer:

it might be 28 sorry if it doesn't help.

6 0

2 years ago

Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?

Sonbull [250]

Answer:

$-6 < k < 2$

Step-by-step explanation:

Given

$y = x^2 - 2x$

$y =kx -4$

Required

Possible values of k

The general quadratic equation is:

$ax^2 + bx + c = 0$

Subtract $y = x^2 - 2x$ and $y =kx -4$

$y - y = x^2 - 2x - kx +4$

$0 = x^2 - 2x - kx +4$

Factorize:

$0 = x^2 +x(-2 - k) +4$

Rewrite as:

$x^2 +x(-2 - k) +4=0$

Compare the above equation to: $ax^2 + bx + c = 0$

$a = 1$

$b= -2-k$

$c =4$

For the equation to have two distinct solution, the following must be true:

$b^2 - 4ac > 0$

So, we have:

$(-2-k)^2 -4*1*4>0$

$(-2-k)^2 -16>0$

Expand

$4 +4k+k^2-16>0$

Rewrite as:

$k^2 + 4k - 16 + 4 >0$

$k^2 + 4k - 12 >0$

Expand

$k^2 + 6k-2k - 12 >0$

Factorize

$k(k + 6)-2(k + 6) >0$

Factor out k + 6

$(k -2)(k + 6) >0$

Split:

$k -2 > 0$ or $k + 6> 0$

So:

$k > 2$ or k $> -6$

To make the above inequality true, we set:

$k < 2$ or $k >-6$

So, the set of values of k is:

$-6 < k < 2$

3 0

2 years ago

Have the points hope who ever gets them needs it

Vlad [161]

Answer:

ty :p

Step-by-step explanation:

6 0

2 years ago

If point A is translated 4 units left and 6 units down, what are the coordinates of A?

Svet_ta [14]

Answer:C (-2, 1)

Step-by-step explanation:

8 0

2 years ago

ILL GIVE BRAINLIESIT HELP

krok68 [10]

D is your answer

Have a good day :)

5 0

2 years ago