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satela [25.4K]
2 years ago
12

Select the system of linear equations that has the solution (-6, 0).

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
3 0

Answer:

B.

• x+2y=-6

• x-2y=-6

Step-by-step explanation:

Try the solution in the equations and choose the set of equations that is true.

___

A. -6+0 ≠ 0 . . . not this system

__

B. -6 +2·0 = -6 . . . true

-6 -2·0 = -6 . . . true . . . . . this system has solution (-6, 0)

__

C. -6 -6·0 ≠ 1 . . . not this system

__

D. 4(-6)+3·0 ≠ -18 . . . not this system

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Answer:

 a - b2

Step-by-step explanation:

STEP  1 :

Trying to factor as a Difference of Squares:

1.1      Factoring:  a-b2  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  a1   is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :

 a - b2

<u><em>HOPE THIS HELPS!</em></u>

<u><em>PLEASE MARK BRAINLIEST! :)</em></u>

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