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Answer with explanation</u>
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Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Set of hypothesis :
![H_0: p=0.43\\\\ H_a:p\neq0.43](https://tex.z-dn.net/?f=H_0%3A%20p%3D0.43%5C%5C%5C%5C%20H_a%3Ap%5Cneq0.43)
Confidence interval for population proportion is given by :-
, where
n= sample size
= sample proportion
and
is the two-tailed z-value for confidence level (c).
As per given ,
Sample size of parents : n= 1085
Number of parents indicated that they were satisfied= 466
Sample proportion : ![\hat{p}=\dfrac{466}{1085}\approx0.429](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D%5Cdfrac%7B466%7D%7B1085%7D%5Capprox0.429)
Critical value for 90% confidence interval :
( by z-value table)
Now, the 90% confidence interval :
Thus , the 90% confidence interval: (0.4043, 0.4537).
Since 0.43 lies in 90% confidence interval , it means we do not have enough evidence to reject the null hypothesis .
i.e. We are have no evidence that parents' attitudes toward the quality of education have changed.
Answer:
radius=9cm
diameter=18cm
Step-by-step explanation:
Answer:
60.16 m
Step-by-step explanation:
Let w = width of river
Using trigonometry :
The width, w of the river is can be calculated thus :
Tan θ = opposite / Adjacent
Tan 76 = w / 15
4.0107809 = w / 15
w = 15 * 4.0107809
w = 60.1617 m
Hence, width of the river is 60.16 m