Simplify the expression 12x^-6y^10X3x^7y

Vikki [24]

Answer:

slope

point-slope form

correlation

Step-by-step explanation:

If you have a line and you know the coordinates of a point on the line, (x1, y1); and you know the slope, m, you can write the equation of the line in point-slope form, y - y1 = m(x - x1). 2 variable data whose point pattern can be represented best by a line is said to have a linear correlation.

The slope, meaning how steep a line is, is represented by the variable m for linear equations.

y - y1 = m(x - x1) is point-slope form, one type of linear equation to represent a straight line. (There is also standard form and slope-intercept form).

Correlation is the relationship between things, like 2 variable data.

8 0

3 years ago

Can some one help me plz??

Hitman42 [59]

The answer is C for this question

5 0

3 years ago

In Triangle ABC, AC is extended through C to D. If

DENIUS [597]

Answer:

X = 5 unit

Step-by-step explanation:

Given as , ABC is a Triangle ,

AC extended to through C to D

∠BAC = 6x + 10

∠ABC = 6x - 10

∠BCD = ∠ 8x + 20

When c extended to D then , ∠BCD is an external angle

∵ External angle = Sum of opposite internal angles

Or ,∠BCD = ∠BAC + ∠ABC

Or, ∠ 8x + 20 = 6x + 10 + 6x - 10

Or, ∠ 8x + 20 = 12x

Or, 12x - 8x = 20

∴ 4x = 20

So, x = $\frac{20}{4}$ = 5

Hence the value of X = 5 unit Answer

8 0

2 years ago

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

2 years ago

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Solve for the varible 1) 7= 1+ 2p 2) -3p + 5= 8

Ilia_Sergeevich [38]

P=3 and p=-1
First you subtract the number without a variable to the other side, so subtract one from seven, and subtract five from eight. After that just divide to make p by its self and you get the answer!!

8 0

3 years ago

Read 2 more answers