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pantera1 [17]
3 years ago
7

Solve the following compound inequality.

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

x > 3 or x < 7

Step-by-step explanation:

2x - 8 > -2 or -2x < -14

2x > 6 or x < 7

x > 3

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What is the zscore with a confidence level of 95% when finding the margin of error for the mean of a normally
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Answer:

Z score with a confidence level of 95% is 1.96

Step-by-step explanation:

The computation of the z score with the confidence level of 95% is shown below:

While determining the margin of error for the normally distributed population from the sample, the z score of the confidence level of 95% is 1.96

The same is to be considered

Therefore the third option is correct

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3 years ago
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How would you simplify the expression represented by the diagram below? Four figures. The first consists of 4 squares each label
Sergeu [11.5K]

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6 x 3c

Step-by-step explanation:

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3 years ago
You have $4150.in a cookie jar. Each month you spend half of the balance. How much do you have after 4 months? (Round your answe
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8 0
3 years ago
I NEED HELP PRONTO PLZZZ HELP ME
forsale [732]

Answer:

12 ÷ 4

Step-by-step explanation:

Let's try to solve the given expression to see if it matches with any of the options guven..

\frac{1}{4}*12

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= \frac{12}{4} (this is equivalent to 12 ÷ 4, which is given in the question)

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4 0
4 years ago
Is (6, –2) a solution to this system of equations? y = –1/6 x − 1 y = 1/6 x − 3
Liula [17]

Answer:

Yes, (6, -2) is a solution to the given system of equations.

Step-by-step explanation:

Please write  y = –1/6 x − 1 y = 1/6 x − 3 as follows, for greater clarity:

y = (–1/6)x − 1

y = (1/6)x − 3

Let's actually solve this system:

y = (–1/6)x − 1

y = (1/6)x − 3

-----------------------

2y = -4, or y = -2

Now find x.  Arbitrarily we choose to use the first equation for this purpose:

y = (-1/6)x - 1.  We set y = -2 and find x:    -2 = (-1/6)x - 1

Combining the constants, we get -1 = (-1/6)x, or 6 = x

Yes, (6, -2) is a solution to the given system of equations.

5 0
3 years ago
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