All categories

3 years ago

Can someone please help me

Mathematics

1 answer:

Blizzard [7]3 years ago

4 0

Answer:

Step-by-step explanation:

rurjrjirudhdbbxhxiidiejr

You might be interested in

What value of b will cause the system to have an infinite number of solutions? A system of equations. y equals 6 x plus b. negat

Natasha_Volkova [10]

The value of b is 6 for which the system of equation will have an infinite number of solutions option third is correct.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have two linear equations:

y = 6x - b ..(1)

$\rm -3x + \dfrac{1}{2}y = -3$ ..(2)

From the second equation:

$\rm -3x + \dfrac{1}{2}y = -3$

-6x + y = -6

After rearranging:

y = 6x - 6 ..(3)

On comparing equation (1) and (3)

b = 6

Thus, the value of b is 6 for which the system of equation will have an infinite number of solutions option third is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

8 0

2 years ago

Find the length of the missing side of the perimeter is 30ft

Svetach [21]

Answer:

5ft

Step-by-step explanation:

7 + 10 + 8 = 25

subtract that form 30

25-30

Thane you get

so the answer is

5!!!!!

also plz mark me brainliest

4 0

3 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found:

$\alpha_{1} = -2\cdot \alpha_{3}$

$\alpha_{1} = -2\cdot k$

$\alpha_{2}= -2\cdot \alpha_{3}$

$\alpha_{2} = -3\cdot k$

It is evident that $\alpha_{1}$ and $\alpha_{2}$ are multiples of $\alpha_{3}$ , which means that the set of vector are linearly dependent.

$p_{1}(t) = 1$ , $p_{2}(t)=t^{2}$ and $p_{3}(t) = 3+3\cdot t +t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1}+3\cdot \alpha_{3} = 0$

$\alpha_{2} + \alpha_{3} = 0$

$3\cdot \alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

4 0

3 years ago

Rachel's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Rachel $4.30 per pound, and typ

Sergio039 [100]

Step 1

Write out the system of equations

$let\text{ x represent pound of Type A coffee and y represent Type B coffee pound }$ $\begin{gathered} 4.30x+5.9y=738.80----(1) \\ x+y=148---(2) \end{gathered}$

Step 2

Find the value of one pound of type A coffee, x

$\begin{gathered} From\text{ equation 2; x+y=148} \\ Therefore \\ y=148-x \end{gathered}$ $\begin{gathered} Substitute\text{ for y in equation 1} \\ 4.30x+5.9(148-x)=738.80 \\ 4.30x+873.2-5.9x=738.80 \\ 873.2-738.80=5.9x-4.3x \\ 134.4=1.6x \\ x=84pounds \end{gathered}$

Therefore the answer will be;

$\begin{gathered} x+y=148 \\ 84+y=148 \\ y=64\text{ pounds} \\ \end{gathered}$

The pounds of type B coffee she used is 64pounds

The pounds of type A coffee she used is 84 pounds

8 0

1 year ago

Item 1<br> Find the dimensions of the square.<br><br> Area = 441 cm²

mafiozo [28]

Answer:

21 cm by 21 cm

Step-by-step explanation:

The formula for the area of a square is A = x^2, where x is the length of any one side of the square. Here,

441 cm² = x²

This actually has two roots: {√441, -√441), but since x must be positive here, to be a dimension of the square, we choose +√441, or +21.

The dimensions of the square are 21 cm by 21 cm.

3 0

3 years ago

Can someone please help me​

Can someone please help me