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3 years ago

Which is the graph of f(x) = –(x + 3)(x + 1)

Mathematics

1 answer:

Sergio [31]3 years ago

4 0

Answer: Please refer to the attachment below

Step-by-step explanation:

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What are the period and phase shift for f(x) = 3 tan(4x + π)?

Y_Kistochka [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now.. with that template above in mind, let's see yours

$\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

7 0

3 years ago

Θ is in Quadrant III and cos^2 0= 1/4

pychu [463]

I think you mean to say $\cos^2\theta=\dfrac14$ . If $\theta$ is in the third quadrant, then $\sin\theta$ and $\cos\theta$ . Recall that

$\sin^2\theta+\cos^2\theta=1\implies\sin\theta=\pm\sqrt{1-\cos^2\theta}$

We expect $\sin\theta$ to be negative, so we take the negative root. We end up with

$\sin\theta=-\sqrt{1-\dfrac14}=-\dfrac{\sqrt3}2$

We also know to expect $\cos\theta$ , so

$\cos\theta=\pm\sqrt{\dfrac14}\implies\cos\theta=-\dfrac12$

By definition, we have

$\cot\theta=\dfrac{\cos\theta}{\sin\theta}$

and so

$\cot\theta=\dfrac{-\frac12}{-\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

7 0

3 years ago

Can someone help me out here?

Zarrin [17]

Answer:

Step-by-step explanation:

10x7=70

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3 years ago

a light flashes every 2 minutes, a second light flashes every 3.5 minutes and a third light flashes every 4 minutes. if all thre

scoray [572]

Take the LCM of the three numbers. Since 2 is a multiple of 4, you can ignore the two and just take the LCM of 4 and 3.5. Since 3.5 is a decimal, the LCM is just 3.5*4 which is 14. That is how many minutes after 8:00 they will flash together again.<span />

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3 years ago

Which of the following DOES NOT have any rectangular faces? A. pentagonal prism B. hexagonal pyramid C. rectangular prism D. squ

docker41 [41]

A pentagonal prism, a rectangular prism, and a square pyramid all have rectangular faces but a hexagonal pyramid does not.

A hexagonal pyramid only consists of a hexagon and triangles. Therefore, the answer is B. Hexagonal Pyramid.

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3 years ago

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