Diameter = 8 cm
radius = diameter/2 = 4 cm
A = pi * r^2
A = pi * (4 cm)^2
A = 16pi cm^2
Answer:
the third one
Step-by-step explanation:
the hypotenuse cannot be gotten by subtracting the two shorter sides
To solve the problem you must apply the corresponding formulas for calculate the area of each figure. Therefore, you have:
1-A cube where the length of each edge is 4 inches: <span>96 square inches
</span><span> A=6a^2=96 inches^2
2- A triangular prism where the area of each base is about 20 square inches, the length of each side of the base is 6 inches, and the height of the prism is 2 inches: </span><span>76 square inches.</span><span>
3- A square pyramid with a base length and slant height of 5 inches: 75</span><span> square inches.
</span><span>A=2(5)(5)+5^2=75 inches^2
4- A rectangular prism with a length of 5 inches, a width of 4 inches, and a height of 3 inches:</span>94 square inches .
A=2(4x5+3x5+3x4)=94 inches^2
Answer:
cot . (x- π/2)= - tanx
Step-by-step explanation:
cot . (x- π/2)= - tanx
cot .x - cot π/2= - tanx
cot π/2= 1/tanπ/2
But tan π/2= ∞
cot π/2 = 1/∞= 0
cotx - 0= - tanx
cot x = - tanx
cosx/sinx= - sinx/cosx Putting values of cot and tan
cosx/ sinx ( sinx/cos x) = -sinx/cos x (sinx/cos x )
Multiplying both sides with sinx/cos x
1= - sin²x/cos²x
cos²x= - sin²x as cosx = -sinx
Answer:
why can't I see the picture on my screen
