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r-ruslan [8.4K]
3 years ago
11

Factor the four-term polynomial. pq - 2r + pr-29

Mathematics
1 answer:
vredina [299]3 years ago
3 0

Your answer should be -18?

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PLEASE HELP FAST!!!!!!!!!!
Rom4ik [11]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
M plain candies come in various colors. According to the MM/Mars Department of Consumer Affairs, the distribution of colors for
ioda
Given that the distribution of colors for plain MM andies is as follows:

<span>Colors      -      Purple   Yellow   Red   Orange   Green   Blue   Brown
Percentage -     20%      20%    20%     10%       10%    10%    10%

Suppose one candy is taken at random from a large bag of plain MM candies, the probability that the candy is purple of orange is given by:

P(purple candy or orange candy) = P(purple candy) + P(orange candy) = 20% + 10% = 30%
</span>
4 0
4 years ago
What is the sum? –18+(–14)<br> a. –32<br> b. –4<br> c. 4<br> d. 32
Jlenok [28]
A.-32
Ignore the negatives and add. Then put back the negatives
6 0
4 years ago
Read 2 more answers
How to solve 2(c 3)=c-13?
kiruha [24]
First we substitute, what that means in here is that 2(c +3)
Or minus I can't see the sign but what we do is we substitute 2 with c so that becomes 2c and 2 with 3 and that becomes 6 which gives us 2c + 6 = c-13
Now we can either add 13 on both sides or subtract 6 on both sides, we can do this because they are like terms even if they are negative because they don't have any variable behind it. We will add 13 because we do the opposite of the sign you are solving some get 2c + 19 = c now we subtract 2c on both sides and we get 19 = -1c and at the end we divide -1 on both side and we get -19 = c or
c = -19.
4 0
3 years ago
20 different comic books will be distributed to five kids. (a) How many ways are there to distribute the comic books if there ar
sveta [45]

Answer:

a) 21684

b) 15504

Step-by-step explanation:

a) Distribute the comic books as follows

only to 1 kid          one way   but we have five kids then  5

to two kids                         C₂₀,₂  =  20! /2! ( 20-2)!    =  20*19 /2  =   190

To three   C₂₀,₃   =  20! /3! ( 20 - 3)!       =  20*19*18 /6               =  1140

To four     C₂₀,₄    =   20 ! / 4! ( 20 - 4 )!   = 20*19*18*17 /4*3*2   =  4845

To five     C₂₀,₅    =    20!  /5! (20 - 5 )!    = 20*19*18*17*16/5*4*3*2*1

C₂₀,₅    =  15504

Then total ways of distribution are:

5 + 190 + 1140 + 4845 + 15504   =  21684

b)   C₂₀,₅  we know from a    that is equal to  15504

7 0
3 years ago
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